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Updated map subclass deserialization test to illustrate a failing condition.

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Gson currently uses LinkedHashMap for an instance if a Map subclass does not define a default constructor.
This commit is contained in:
Inderjeet Singh 2012-03-11 21:37:13 +00:00
parent 4c629347da
commit 15c2ae7548
1 changed files with 6 additions and 5 deletions
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11
gson/src/test/java/com/google/gson/functional/MapTest.java
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@ -157,7 +157,7 @@ public class MapTest extends TestCase {
} }
public void testParameterizedMapSubclassSerialization() { public void testParameterizedMapSubclassSerialization() {
MyParameterizedMap<String, String> map = new MyParameterizedMap<String, String>(); MyParameterizedMap<String, String> map = new MyParameterizedMap<String, String>(10);
map.put("a", "b"); map.put("a", "b");
Type type = new TypeToken<MyParameterizedMap<String, String>>() {}.getType(); Type type = new TypeToken<MyParameterizedMap<String, String>>() {}.getType();
String json = gson.toJson(map, type); String json = gson.toJson(map, type);
@ -172,11 +172,12 @@ public class MapTest extends TestCase {
assertEquals(2, map.get("b").intValue()); assertEquals(2, map.get("b").intValue());
} }
@SuppressWarnings({ "unused", "serial" })
private static class MyParameterizedMap<K, V> extends LinkedHashMap<K, V> { private static class MyParameterizedMap<K, V> extends LinkedHashMap<K, V> {
private static final long serialVersionUID = 1L; final int foo;
MyParameterizedMap(int foo) {
@SuppressWarnings("unused") this.foo = foo;
int foo = 10; }
} }
public void testMapSubclassSerialization() { public void testMapSubclassSerialization() {