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Fix typo in UserGuide (#1572)

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Prempal Singh 2019-09-18 23:09:14 +05:30 committed by inder123
parent 3958b1f78d
commit 0409a2ecab
1 changed files with 1 additions and 1 deletions
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UserGuide.md
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@ -248,7 +248,7 @@ gson.toJson(foo); // May not serialize foo.value correctly
gson.fromJson(json, foo.getClass()); // Fails to deserialize foo.value as Bar
```
The above code fails to interpret value as type Bar because Gson invokes `list.getClass()` to get its class information, but this method returns a raw class, `Foo.class`. This means that Gson has no way of knowing that this is an object of type `Foo<Bar>`, and not just plain `Foo`.
The above code fails to interpret value as type Bar because Gson invokes `foo.getClass()` to get its class information, but this method returns a raw class, `Foo.class`. This means that Gson has no way of knowing that this is an object of type `Foo<Bar>`, and not just plain `Foo`.
You can solve this problem by specifying the correct parameterized type for your generic type. You can do this by using the [`TypeToken`](https://static.javadoc.io/com.google.code.gson/gson/2.8.5/com/google/gson/reflect/TypeToken.html) class.